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The least number, which when divided by 12, 15, 20 and 54 leaves in each case a remainder of 8 is:

A. 504

B. 536

C. 544

D. 548

Answer: Option D

Solution(By Examveda Team)

Required number
= (L.C.M. of 12, 15, 20, 54) + 8
= 540 + 8
= 548

This Question Belongs to Arithmetic Ability >> Problems On H.C.F And L.C.M

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