The least number, which when divided by 12, 15, 20 and 54 leaves in each case a remainder of 8 is:
A. 504
B. 536
C. 544
D. 548
Answer: Option D
Solution(By Examveda Team)
Required number= (L.C.M. of 12, 15, 20, 54) + 8
= 540 + 8
= 548
Related Questions on Problems on H.C.F and L.C.M
Join The Discussion