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Problems on H.C.F and L.C.M
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The least number which when divided by 4, 6, 8, 12 and 16 leaves remainder of 2 in each case is = ?

Answer & Solution
Correct Answer: Option C
LCM of (4, 6, 8, 12, 16)
⇒ 16 × 3 = 48
∴ The number when divided by (4, 6, 8, 12, 16) leaves remainder 2 is
= 48 + 2
= 50
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