The number of integers in between 100 and 600, which are divisible by 4 and 6 both, is :
A. 40
B. 42
C. 41
D. 50
Answer: Option C
Solution(By Examveda Team)
Take L.C.M. of and 6 = 12 and numbers should be divisible by 12.First number (after 100) = 108
Last of integers
$$\eqalign{ & = \frac{{{\text{ Last term }} - {\text{ First term}}}}{{{\text{Difference}}}} + 1 \cr & = \frac{{588 - 108}}{{12}} + 1 \cr & = \frac{{480}}{{12}} + 1 \cr & = 40 + 1 \cr & = 41 \cr} $$
Related Questions on Number System
Three numbers are in ratio 1 : 2 : 3 and HCF is 12. The numbers are:
A. 12, 24, 36
B. 11, 22, 33
C. 12, 24, 32
D. 5, 10, 15
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