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The number of integers in between 100 and 600, which are divisible by 4 and 6 both, is :
Answer & Solution
Correct Answer:
Option
C
Take L.C.M. of and 6 = 12 and numbers should be divisible by 12.
First number (after 100) = 108
Last of integers
$$\eqalign{ & = \frac{{{\text{ Last term }} - {\text{ First term}}}}{{{\text{Difference}}}} + 1 \cr & = \frac{{588 - 108}}{{12}} + 1 \cr & = \frac{{480}}{{12}} + 1 \cr & = 40 + 1 \cr & = 41 \cr} $$
First number (after 100) = 108
Last of integers
$$\eqalign{ & = \frac{{{\text{ Last term }} - {\text{ First term}}}}{{{\text{Difference}}}} + 1 \cr & = \frac{{588 - 108}}{{12}} + 1 \cr & = \frac{{480}}{{12}} + 1 \cr & = 40 + 1 \cr & = 41 \cr} $$
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