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This question belongs to Arithmetic Ability Percentage
Percentage
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The numbers are respectively $$12\frac{1}{2}\% $$  and $$25\% $$ more than a third number. The as a percentage of the second number is :

Answer & Solution
Correct Answer: Option D
Let the third number be $$x$$
Then, first number :
= $$112\frac{1}{2}\% $$  of $$x$$
= $$\frac{9x}{8}$$
Second number :
= 125% of $$x$$
= $$\frac{5x}{4}$$
∴ Required percentage :
= $$\left( {\frac{{9x}}{8} \times \frac{{4}}{{5x}} \times 100} \right)$$   %
= 90%
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