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The population of a town is 1771561. If it had been increasing at 10% per annum, its population 6 years ago was :
Answer & Solution
Correct Answer:
Option
A
Population of 6 years ago :
$$\eqalign{ & = \left[ {\frac{{1771561}}{{{{\left( {1 + \frac{{10}}{{100}}} \right)}^6}}}} \right] \cr & = 1771561 \times {\left( {\frac{{10}}{{11}}} \right)^6} \cr & = \frac{{1771561 \times 1000000}}{{1771561}} \cr & = 1000000 \cr} $$
$$\eqalign{ & = \left[ {\frac{{1771561}}{{{{\left( {1 + \frac{{10}}{{100}}} \right)}^6}}}} \right] \cr & = 1771561 \times {\left( {\frac{{10}}{{11}}} \right)^6} \cr & = \frac{{1771561 \times 1000000}}{{1771561}} \cr & = 1000000 \cr} $$
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