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The price of an article was first increased by 10% and then again by 20%. If the last increased price was Rs. 33, the original price was :
Answer & Solution
Correct Answer:
Option
D
Let the original price = 100x
Article price 1st increased by 10%. i.e price of article become 100x + 100x of 10% = 110x
And then the article price increased by 20% i.e. price of article become 110x + 110x of 20% = 132x
According to the question,
132x = 33
⇒ x = $$\frac{33}{132}$$
⇒ x = $$\frac{1}{4}$$
Therefore Original price of Article is
= 100 × $$\frac{1}{4}$$
= Rs. 25
Article price 1st increased by 10%. i.e price of article become 100x + 100x of 10% = 110x
And then the article price increased by 20% i.e. price of article become 110x + 110x of 20% = 132x
According to the question,
132x = 33
⇒ x = $$\frac{33}{132}$$
⇒ x = $$\frac{1}{4}$$
Therefore Original price of Article is
= 100 × $$\frac{1}{4}$$
= Rs. 25
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