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The price of an article was increased by r%. Later the new price was decreased by r%. If the latest price was Rs. 1, then the original price was :
Answer & Solution
Correct Answer:
Option
D
r% = $$\frac{r}{100}$$
According to the question,
(100 + r) (100 - r) units = Rs. 1
(10000 - r2) units = Rs. 1
1 unit = $$\left( {\frac{{1}}{{10000 - {r^2}}}} \right)$$
Original price = $$\left( {\frac{{10000}}{{10000 - {r^2}}}} \right)$$
| Initial Price | Final | |
| 100 | (100 + r) | |
| 100 | (100 - r) | |
| 10000 | (100 + r) (100 - r) |
According to the question,
(100 + r) (100 - r) units = Rs. 1
(10000 - r2) units = Rs. 1
1 unit = $$\left( {\frac{{1}}{{10000 - {r^2}}}} \right)$$
Original price = $$\left( {\frac{{10000}}{{10000 - {r^2}}}} \right)$$
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