The product of any three consecutive natural numbers is always divisible by :
A. 3
B. 6
C. 9
D. 15
Answer: Option B
Solution(By Examveda Team)
Let the required product be n (n + 1) (n + 2)Then,
n = 1 ⇒ n (n + 1) (n + 2) = (1 × 2 × 3) = 6
n = 2 ⇒ n (n + 1) (n + 2) = (2 × 3 × 4) = 24
n = 3 ⇒ n (n + 1) (n + 2) = (3 × 4 × 5) = 60
So, each such product is divisible by 6
Related Questions on Number System
Three numbers are in ratio 1 : 2 : 3 and HCF is 12. The numbers are:
A. 12, 24, 36
B. 11, 22, 33
C. 12, 24, 32
D. 5, 10, 15
Join The Discussion