The random variable X takes on the values 1, 2 (or) 3 with probabilities $$\frac{{2 + 5{\text{P}}}}{5},\frac{{1 + 3{\text{P}}}}{5}$$ and $$\frac{{1.5 + 2{\text{P}}}}{5}$$ respectively the values of P and E(X) are respectively.
A. 0.05, 1.87
B. 1.90, 5.87
C. 0.05, 1.10
D. 0.25, 1.40
Answer: Option A

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