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The remainder of (3)67! divided by 80 is :
Answer & Solution
Correct Answer:
Option
B
Since, $${3^4} = 81$$ gives remainder 1 on divided by 80
So, $$\frac{{{3^{4n}}}}{{80}}$$ gives remainder 1
Thus, $$\frac{{{3^{67!}}}}{{80}}$$ will also give the remainder as 1
Since, 67! = 4n for a positive integer n
So, $$\frac{{{3^{4n}}}}{{80}}$$ gives remainder 1
Thus, $$\frac{{{3^{67!}}}}{{80}}$$ will also give the remainder as 1
Since, 67! = 4n for a positive integer n
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LoginBy Sanjay Mohan Bhatnagar (www.mathsacad99.com)