The simplest reduction to the lowest terms of $$\frac{{116690151}}{{427863887}}$$ is = ?
A. $$\frac{{3}}{{11}}$$
B. $$\frac{{7}}{{11}}$$
C. $$\frac{{11}}{{3}}$$
D. None of these
Answer: Option A
Solution(By Examveda Team)
$$\eqalign{ & {\text{116690151}}\overline {){\text{427863887(}}} {\text{3}} \cr & \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,{\text{350070453}} \cr & \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\overline {{\text{77793434)116690151(}}} 1 \cr & \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,{\text{77793434}} \cr & \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\overline {{\text{38896717)77793434(}}} {\text{2}} \cr & \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\frac{{77793434}}{ \times } \cr & {\text{So, H}}{\text{.C}}{\text{.F of 116690151 and 427863887}} \cr & {\text{ = 38896717}} \cr & \therefore \frac{{116690151}}{{427863887}} = \frac{{116690151 \div 38896717}}{{427863887 \div 38896717}} \cr & \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\, = \frac{3}{{11}} \cr} $$Related Questions on Problems on H.C.F and L.C.M
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