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The smallest five digit number which is divisible by 12, 18 and 21 is :
Answer & Solution
Correct Answer:
Option
A
We know,
Smallest five digit number is = 10000
L.C.M. of 12, 18, 21 = 252
10000 is divided by 252
then the remainder is 172
Difference = 252 - 172 = 80
Then number is = 10000 + 80 = 10080
Smallest five digit number is = 10000
L.C.M. of 12, 18, 21 = 252
10000 is divided by 252
then the remainder is 172
Difference = 252 - 172 = 80
Then number is = 10000 + 80 = 10080
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