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Examveda

The smallest number which when diminished by 7, is divisible 12, 16, 18, 21 and 28 is:

A. 1008

B. 1015

C. 1022

D. 1032

Answer: Option B

Solution(By Examveda Team)

Required number = (L.C.M. of 12,16, 18, 21, 28) + 7
   = 1008 + 7
   = 1015

This Question Belongs to Arithmetic Ability >> Problems On H.C.F And L.C.M

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