The smallest number, which when increased by 5 is divisible by each of 24, 32, 36 and 64 is ?
A. 869
B. 859
C. 571
D. 427
Answer: Option C
Solution(By Examveda Team)
LCM of (24, 32, 36, 64)⇒ 8 × 3 × 4 × 3 × 2 = 576
Required number is 576 - 5 = 571
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