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Examveda

The smallest number, which when increased by 5 is divisible by each of 24, 32, 36 and 64 is ?

A. 869

B. 859

C. 571

D. 427

Answer: Option C

Solution(By Examveda Team)

LCM of (24, 32, 36, 64)
⇒ 8 × 3 × 4 × 3 × 2 = 576
Required number is 576 - 5 = 571

This Question Belongs to Arithmetic Ability >> Problems On H.C.F And L.C.M

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