The solution of the differential equation, for t > 0, y''(t) + 2y'(t) + y(t) = 0 with initial conditions y(0) = 0 and y'(0) = 1, is (u(t) denotes the unit step function),
A. te-tu(t)
B. (e-t - te-t)u(t)
C. (-e-t + te-t)u(t)
D. e-tu(t)
Answer: Option A

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