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Square Root and Cube Root
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The square root of $$\left( {{{272}^2} - {{128}^2}} \right)$$   is = ?

Answer & Solution
Correct Answer: Option C
$$\eqalign{ & = \sqrt {\left( {{{272}^2} - {{128}^2}} \right)} \cr & = \sqrt {\left( {272 + 128} \right)\left( {272 - 128} \right)} \cr & = \sqrt {400 \times 144} \cr & = \sqrt {57600} \cr & = 240 \cr} $$
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