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The sum of three consecutive natural numbers is always divisible by . . . . . . . .?
Answer & Solution
Correct Answer:
Option
A
Let the number be x, x + 1, x + 2
Sum = x + x + 1 + x + 2
= 3x + 3
= 3(x + 1)
It is always divisible by 3
Sum = x + x + 1 + x + 2
= 3x + 3
= 3(x + 1)
It is always divisible by 3
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