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The sum of three consecutive odd natural numbers each divisible by 3 is 63. What is the largest among them ?
Answer & Solution
Correct Answer:
Option
C
$$\eqalign{
& \left( x \right) + \left( {x + 6} \right) + \left( {x + 12} \right) = 63 \cr
& 3x + 18 = 63 \cr
& 3x = 45 \cr
& x = 15 \cr
& {\text{So,the largest number is}} \cr
& {\text{ = }}15 + 12 \cr
& = 27 \cr} $$
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