The sum of three consecutive odd natural numbers each divisible by 3 is 63. What is the largest among them ?
A. 21
B. 24
C. 27
D. 36
Answer: Option C
Solution(By Examveda Team)
$$\eqalign{ & \left( x \right) + \left( {x + 6} \right) + \left( {x + 12} \right) = 63 \cr & 3x + 18 = 63 \cr & 3x = 45 \cr & x = 15 \cr & {\text{So,the largest number is}} \cr & {\text{ = }}15 + 12 \cr & = 27 \cr} $$Related Questions on Number System
Three numbers are in ratio 1 : 2 : 3 and HCF is 12. The numbers are:
A. 12, 24, 36
B. 11, 22, 33
C. 12, 24, 32
D. 5, 10, 15
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