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The sum of three numbers is 252. If the first number is thrice the second and third number is two-third of the first, then the second number is :
Answer & Solution
Correct Answer:
Option
C
Let the number is a, b, c
a = 3b $$\frac{a}{b}$$ = $$\frac{3}{1}$$
c = $$\frac{2}{3}$$a $$\frac{c}{a}$$ = $$\frac{2}{3}$$
c : a : b = 2 : 3 : 1
So, (2 + 3 + 1) = 252 units
6 units → 252
1 unit → 42
3 units → 42 × 3
So, second number is = 42
a = 3b $$\frac{a}{b}$$ = $$\frac{3}{1}$$
c = $$\frac{2}{3}$$a $$\frac{c}{a}$$ = $$\frac{2}{3}$$
| c | a | b |
| 2 | 3 | |
| 3 | 1 |
So, (2 + 3 + 1) = 252 units
6 units → 252
1 unit → 42
3 units → 42 × 3
So, second number is = 42
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