The table below gives values of a function F(x) obtained for values of x at intervals of 0.25.
| x | 0 | 0.25 | 0.5 | 0.75 | 1.0 |
| F(x) | 1 | 0.9412 | 0.8 | 0.64 | 0.50 |
The value of the integral of the function between the limits 0 to 1 using Simpson's rule is
A. 0.7854
B. 2.3562
C. 3.1416
D. 7.5000
Answer: Option A
This Question Belongs to Engineering Maths >> Numerical Methods
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