The transfer function of a zero-order-hold system is
A. $$\left( {\frac{1}{s}} \right)\left( {1 + {e^{ - sT}}} \right)$$
B. $$\left( {\frac{1}{s}} \right)\left( {1 - {e^{ - sT}}} \right)$$
C. $$1 - \left( {\frac{1}{s}} \right){e^{ - sT}}$$
D. $$1 + \left( {\frac{1}{s}} \right){e^{ - sT}}$$
Answer: Option B

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