The value of (d^{s + t} ÷ d^s) ÷ d^t would be

Solution (By Examveda Team)

(d^{s + t} ÷ d^s) ÷ d^t
= $$\left( {\frac{{{{\text{d}}^{{\text{s}} + {\text{t}}}}}}{{{{\text{d}}^{\text{s}}}}}} \right)$$  ÷ d^t
= (d^{s + t - s}) ÷ d^t
= (d^t) ÷ d^t
= $$\frac{{{{\text{d}}^{\text{t}}}}}{{{{\text{d}}^{\text{t}}}}}$$
= d^{t - t}
= d⁰
= 1