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The value of (ds + t ÷ ds) ÷ dt would be
Answer & Solution
Correct Answer:
Option
B
(ds + t ÷ ds) ÷ dt
= $$\left( {\frac{{{{\text{d}}^{{\text{s}} + {\text{t}}}}}}{{{{\text{d}}^{\text{s}}}}}} \right)$$ ÷ dt
= (ds + t - s) ÷ dt
= (dt) ÷ dt
= $$\frac{{{{\text{d}}^{\text{t}}}}}{{{{\text{d}}^{\text{t}}}}}$$
= dt - t
= d0
= 1
= $$\left( {\frac{{{{\text{d}}^{{\text{s}} + {\text{t}}}}}}{{{{\text{d}}^{\text{s}}}}}} \right)$$ ÷ dt
= (ds + t - s) ÷ dt
= (dt) ÷ dt
= $$\frac{{{{\text{d}}^{\text{t}}}}}{{{{\text{d}}^{\text{t}}}}}$$
= dt - t
= d0
= 1
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