The value of : $$\left( {1 + \frac{1}{2}} \right)$$ $$\left( {1 + \frac{1}{3}} \right)$$ $$\left( {1 + \frac{1}{4}} \right)$$ ..... $$\left( {1 + \frac{1}{120}} \right)$$

$$\eqalign{ & \left( {1 + \frac{1}{2}} \right)\left( {1 + \frac{1}{3}} \right)\left( {1 + \frac{1}{4}} \right).....\left( {1 + \frac{1}{{120}}} \right) \cr & = \frac{3}{2} \times \frac{4}{3} \times \frac{5}{4}.........\frac{{121}}{{120}} \cr & = \frac{{121}}{2} \cr & = 60.5{\text{ Ans}}. \cr} $$