There are 8 equidistant points A, B, C, D, E, F, G and H (in same order) on a circle. What is the value of ∠FDH (in degrees)?

Solution (By Examveda Team)

$$\eqalign{ & \angle FOH = \frac{{\angle FOB}}{2} = {90^ \circ } \cr & \left[ {\therefore FOB{\text{ is a straight line}}} \right] \cr & \angle HDF = \frac{{\angle FOH}}{2} = \frac{{{{90}^ \circ }}}{2} = {45^ \circ } \cr} $$