ΔABC a right angled triangle has ∠B = 90° and AC is hypotenuse. D is its circumcenter and AB = 3 cms, BC = 4 cms. The value of BD is
A. 3 cms
B. 4 cms
C. 2.5 cms
D. 5.5 cms
Answer: Option C
Solution (By Examveda Team)
AC $$ = \sqrt {{3^2} + {4^2}} = \sqrt {9 + 16} $$
AC = 5
∵ D is circumcenter, it is equidistant from all the center
So AD = CD = BD = $$\frac{5}{2}$$ = 2.5 cm
This Question Belongs to Arithmetic Ability >> Geometry
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