ΔABC and ΔDBC are on the same base BC but on opposite sides of it. AD and BC intersect each other at O. If AO = a cm, DO = b cm and the area of ΔABC = x cm², then what is the area (in cm²) of ΔDBC?

A) $$\frac{a}{b}x$$ B) $$\frac{{ab}}{2}x$$ C) $$\frac{{bx}}{a}$$ D) $$\frac{{\left( {a + b} \right)}}{2}x$$

Answer & Solution

Correct Answer: Option C

Area of ΔABC : Area of ΔBDC = a : b = ak : bk
$$\eqalign{ & ak = x \cr & k = \frac{x}{a} \cr & bk = b \times \frac{x}{a} = \frac{{bx}}{a} \cr} $$
Geometry mcq question image

Question posted by Examveda

Community

Join the Discussion

Join the discussion

Login to post a comment or share your explanation.

No comments yet Be the first to discuss this question.

Keep Learning

ABC and DBC are on the same base BC but on...

ΔABC and ΔDBC are on the same base BC but on opposite sides of it. AD and BC intersect each other at O. If AO = a cm, DO = b cm and the area of ΔABC = x cm2, then what is the area (in cm2) of ΔDBC?

Join the Discussion

Related Questions on Geometry

ΔABC and ΔDBC are on the same base BC but on opposite sides of it. AD and BC intersect each other at O. If AO = a cm, DO = b cm and the area of ΔABC = x cm², then what is the area (in cm²) of ΔDBC?