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Two circles C1 and C2 touch each other internally at P. Two lines PCA and PDB meet the circles C1 in C, D and C2 in A, B respectively. If ∠BDC = 120°, then the value of ∠ABP is equal to
Answer & Solution
Correct Answer:
Option
A
According to question
Given:
∠BDC = 120°, ∠ABP =?
∴ ∠CDP = 180° - ∠BDC
∠CDP = 180° - 120°
∠CDP = 60°
CD || AB
∴ ∠CDP = ∠ABP = 60°
Given:
∠BDC = 120°, ∠ABP =?
∴ ∠CDP = 180° - ∠BDC
∠CDP = 180° - 120°
∠CDP = 60°
CD || AB
∴ ∠CDP = ∠ABP = 60°
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