Two pipes can fill the cistern in 10hr and 12 hr respectively, while the third empty it in 20hr. If all pipes are opened simultaneously, then the cistern will be filled in:

A. 7.5 hr

B. 8 hr

C. 8.5 hr

D. 10 hr

Answer: Option A

Solution(By Examveda Team)

Work done by all the tanks working together in 1 hour,
$$ \Rightarrow \frac{1}{{10}} + \frac{1}{{12}} - \frac{1}{{20}} = \frac{2}{{15}}$$
Hence, tank will be filled in $$\frac{{15}}{2}$$ = 7.5 hour.