Two students appeared at an examination. One of them secured 9 marks more than the other and his marks was 56% of the sum of their marks. The marks obtained by them are:

Let their marks be (x + 9) and x
Then,
$$\eqalign{ & x + 9 = \frac{{56}}{{100}}\left( {x + 9 + x} \right) \cr & \Rightarrow 25\left( {x + 9} \right) = 14\left( {2x + 9} \right) \cr & \Rightarrow 3x = 99 \cr & \Rightarrow x = 33 \cr} $$
So, their marks are 42 and 33