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Two trains are running at 40 km/hr and 20 km/hr respectively in the same direction. Fast train completely passes a man sitting in the slower train in 5 seconds. What is the length of the fast train?

A. 23 m

B. $$23\frac{2}{9}$$ m

C. $$27\frac{7}{9}$$ m

D. 29 m

Answer: Option C

Solution(By Examveda Team)

$$\eqalign{ & {\text{Relative}}\,{\text{speed}} = \left( {40 - 20} \right)\,{\text{km/hr}} \cr & = \left( {20 \times \frac{5}{{18}}} \right)\,{\text{m/sec}} \cr & = {\frac{{50}}{9}} \,{\text{m/sec}} \cr & \therefore {\text{Length}}\,{\text{of}}\,{\text{faster}}\,{\text{train}} \cr & = \left( {\frac{{50}}{9} \times 5} \right)\,m \cr & = \frac{{250}}{9}\,m \cr & = 27\frac{7}{9}\,m \cr} $$

This Question Belongs to Arithmetic Ability >> Problems On Trains

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Comments ( 2 )

  1. Vidya Shettangoura
    Vidya Shettangoura :
    1 year ago

    Why you taken 18 here

  2. Brindha T
    Brindha T :
    6 years ago

    both the trains are moving in same direction. So the relative speed is (speed of faster- speed of lower train)=40-20=20km/hr=20*5/18=50/9 m/s.
    Distance=speed*time
    time=5 seconds
    Now,
    d=(50/9)*5=250/9=27 7/9 m

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