What is the output of the following code?
#include<stdio.h>
#include<string.h>
int max_num(int a, int b)
{
if(a > b)
return a;
return b;
}
int lps(char *str1)
{
int i,j,len;
len = strlen(str1);
char str2[len + 1];
strcpy(str2, str1);
strrev(str2);
int arr[len + 1][len + 1];
for(i = 0; i <= len; i++)
arr[i][0] = 0;
for(i = 0; i <= len; i++)
arr[0][i] = 0;
for(i = 1; i <= len; i++)
{
for(j = 1; j <= len; j++)
{
if(str1[i-1] == str2[j - 1])
arr[i][j] = 1 + arr[i - 1][j - 1];
else
arr[i][j] = max_num(arr[i - 1][j], arr[i][j - 1]);
}
}
return arr[len][len];
}
int main()
{
char str1[] = "abcd";
int ans = lps(str1);
printf("%d",ans);
return 0;
}
#include<stdio.h>
#include<string.h>
int max_num(int a, int b)
{
if(a > b)
return a;
return b;
}
int lps(char *str1)
{
int i,j,len;
len = strlen(str1);
char str2[len + 1];
strcpy(str2, str1);
strrev(str2);
int arr[len + 1][len + 1];
for(i = 0; i <= len; i++)
arr[i][0] = 0;
for(i = 0; i <= len; i++)
arr[0][i] = 0;
for(i = 1; i <= len; i++)
{
for(j = 1; j <= len; j++)
{
if(str1[i-1] == str2[j - 1])
arr[i][j] = 1 + arr[i - 1][j - 1];
else
arr[i][j] = max_num(arr[i - 1][j], arr[i][j - 1]);
}
}
return arr[len][len];
}
int main()
{
char str1[] = "abcd";
int ans = lps(str1);
printf("%d",ans);
return 0;
}A. 0
B. 1
C. 2
D. 3
Answer: Option B

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