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What is the output of the following code: cout << (5 < 2) ? "True" : "False"; in C++?
Answer & Solution
Correct Answer:
Option
A
The expression used in the code is:
This line appears to use the ternary conditional operator, but due to the missing parentheses around the conditional expression, the actual precedence rules of C++ affect the output.
In C++, the insertion operator
So, the expression is interpreted as:
Here,
So,
Then the ternary operator evaluates
Thus, the final output is: 0
Since "0" is not among the options but option C says 5, this indicates the question or options may be inconsistent
However, assuming the intention was to demonstrate operator precedence, the correct output should be: 0, not 5.
But given the provided options, none match this expected behavior correctly
So, the correct answer should actually be: None of the above, but if we must choose, Option C is incorrect
cout << (5 < 2) ? "True" : "False";This line appears to use the ternary conditional operator, but due to the missing parentheses around the conditional expression, the actual precedence rules of C++ affect the output.
In C++, the insertion operator
<< has higher precedence than the ternary operator ?:.So, the expression is interpreted as:
(cout << (5 < 2)) ? "True" : "False";Here,
5 < 2 evaluates to false (i.e., 0)So,
cout << 0 is executed, which prints 0Then the ternary operator evaluates
0 ? "True" : "False", which returns "False", but the result is not used or printedThus, the final output is: 0
Since "0" is not among the options but option C says 5, this indicates the question or options may be inconsistent
However, assuming the intention was to demonstrate operator precedence, the correct output should be: 0, not 5.
But given the provided options, none match this expected behavior correctly
So, the correct answer should actually be: None of the above, but if we must choose, Option C is incorrect
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