What is the output of the following program?

#include<stdio.h>
int main()
{
      int coins[10]={1,3,4},lookup[100];
      int i,j,tmp,num_coins = 3,sum=10;
      lookup[0]=0;
      for(i=1;i<=sum;i++)
      {
	    int min_coins = i;
	    for(j=0;j<num_coins;j++)
	    {
	         tmp=i-coins[j];
	         if(tmp<0)
	          continue;
	         if(lookup[tmp] < min_coins)
		 min_coins=lookup[tmp];
	    }
	    lookup[i] = min_coins + 1;
      }
      printf("%d",lookup[sum]);
      return 0;
}

A. 2

B. 3

C. 4

D. 5

Answer: Option B