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What is the smallest number by which 3600 be divided to make it a perfect cube ?
Answer & Solution
Correct Answer:
Option
D
$$3600 = {2^3} \times {5^2} \times {3^2} \times 2$$
To make it a perfect cube, it must be divided by $${5^2} \times {3^2} \times 2,i.e.,450$$
To make it a perfect cube, it must be divided by $${5^2} \times {3^2} \times 2,i.e.,450$$
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