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What is the sum of all the common terms between the given series S1 and S2?
What is the sum of all the common terms between the given series S1 and S2?
S1 = 2, 9, 16, . . . . . ., 632
S2 = 7, 11, 15, . . . . . ., 743
Answer & Solution
Correct Answer:
Option
C
S1 = 2, 9, 16, . . . . . ., 632
S2 = 7, 11, 15, . . . . . ., 743
S1 = 2, 9, 16, 23, 30, 37, 44, 51 . . . . . .
S2 = 7, 11, 15, 19, 23, 27, 31, 35, 39, 43, 47, 51, . . . . . .
Number of terms in $${{\text{S}}_1} = \frac{{632 - 2}}{7} + 1 = 91$$
∵ In S1 there is no further terms beyond 632 therefore there is no common terms.
∴ Number of terms in series S1 = 91
If this series start from the 23 then number of terms = 91 - 3 = 88
Now, number of common terms in both series S1 and S2 = $$\frac{{88}}{7}$$ = 22 = n
Now, common terms 23, 51, . . . . . . 22
$$\eqalign{ & {\text{Sum}} = \frac{n}{2}\left[ {2a + \left( {n - 1} \right)d} \right] \cr & = 11\left[ {46 + 21 \times 28} \right] \cr & = 11\left[ {46 + 588} \right] \cr & = 11 \times 634 \cr & = 6974 \cr} $$
S2 = 7, 11, 15, . . . . . ., 743
S1 = 2, 9, 16, 23, 30, 37, 44, 51 . . . . . .
S2 = 7, 11, 15, 19, 23, 27, 31, 35, 39, 43, 47, 51, . . . . . .
Number of terms in $${{\text{S}}_1} = \frac{{632 - 2}}{7} + 1 = 91$$
∵ In S1 there is no further terms beyond 632 therefore there is no common terms.
∴ Number of terms in series S1 = 91
If this series start from the 23 then number of terms = 91 - 3 = 88
Now, number of common terms in both series S1 and S2 = $$\frac{{88}}{7}$$ = 22 = n
Now, common terms 23, 51, . . . . . . 22
$$\eqalign{ & {\text{Sum}} = \frac{n}{2}\left[ {2a + \left( {n - 1} \right)d} \right] \cr & = 11\left[ {46 + 21 \times 28} \right] \cr & = 11\left[ {46 + 588} \right] \cr & = 11 \times 634 \cr & = 6974 \cr} $$
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