What will be the correct output of the following program? #includelt;string.h> void main() char str[] = "C EXAMINATION", rev[17]; int i = strlen(str), j=0; for( ; i>=0; rev[j++] = str[i--]) rev[j] = str[j] ; puts(rev);

What will be the correct output of the following program #include&lt...

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Arrays and Strings

What will be the correct output of the following program?

#include<string.h>
void main()
{
   char str[] = "C EXAMINATION", rev[17];
   int i = strlen(str), j=0;
   for( ; i>=0; rev[j++] = str[i--])
   rev[j] =  str[j] ;
   puts(rev);
}

A) NOITANIMAXE C B) NOITANIMAXE C) C D) No output at all. E) Syntax error

Answer & Solution

Correct Answer: Option D

As i is with the length of string and hence in array rev the contents are copied as "\0 NOITANIMAXE C". But while displaying those contents with puts function it stops because of the first character '\0' and hence no output.

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What will be the correct output of the following program #include&lt...

What will be the correct output of the following program? #include<string.h> void main() { char str[] = "C EXAMINATION", rev[17]; int i = strlen(str), j=0; for( ; i>=0; rev[j++] = str[i--]) rev[j] = str[j] ; puts(rev); }

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What will be the correct output of the following program?

`#include<string.h> void main() { char str[] = "C EXAMINATION", rev[17]; int i = strlen(str), j=0; for( ; i>=0; rev[j++] = str[i--]) rev[j] = str[j] ; puts(rev); }`