What will be the least number which when doubled will be exactly divisible by 12, 18, 21 and 30 ?
A. 196
B. 630
C. 1260
D. 2520
Answer: Option B
Solution(By Examveda Team)
12 = 2 × 2 × 318 = 2 × 3 × 3
21 = 3 × 7
30 = 2 × 3 × 5
L.C.M. of 12, 18, 21 30 = 2 × 3 × 2 × 3 × 7 × 5 = 1260
Required number = $$\frac{{1260}}{2}$$ = 630
This Question Belongs to Arithmetic Ability >> Problems On H.C.F And L.C.M
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