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What will be the least number which when doubled will be exactly divisible by 12, 18, 21 and 30 ?
Answer & Solution
Correct Answer:
Option
B
12 = 2 × 2 × 3
18 = 2 × 3 × 3
21 = 3 × 7
30 = 2 × 3 × 5
L.C.M. of 12, 18, 21 30 = 2 × 3 × 2 × 3 × 7 × 5 = 1260
Required number = $$\frac{{1260}}{2}$$ = 630
18 = 2 × 3 × 3
21 = 3 × 7
30 = 2 × 3 × 5
L.C.M. of 12, 18, 21 30 = 2 × 3 × 2 × 3 × 7 × 5 = 1260
Required number = $$\frac{{1260}}{2}$$ = 630
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