What will be the output?
public class Test{
public static void main(String[] args){
String value = "abc";
changeValue(value);
System.out.println(value);
}
public static void changeValue(String a){
a = "xyz";
}
}
public class Test{
public static void main(String[] args){
String value = "abc";
changeValue(value);
System.out.println(value);
}
public static void changeValue(String a){
a = "xyz";
}
}A. abc
B. xyz
C. Compilation fails
D. Compilation clean but no output
E. None of these
Answer: Option A
Solution (By Examveda Team)
Java pass reference as value. passing the object reference, and not the actual object itself. Simply reassigning to the parameter used to pass the value into the method will do nothing, because the parameter is essentially a local variable.
This Question Belongs to Java Program >> Constructors And Methods
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