What will be the output of the following C code?
#include <stdio.h>
int main()
{
int ary[2][3][4], j = 20;
ary[0][0] = &j;
printf("%d\n", *ary[0][0]);
}
#include <stdio.h>
int main()
{
int ary[2][3][4], j = 20;
ary[0][0] = &j;
printf("%d\n", *ary[0][0]);
}A. Compile time error
B. 20
C. Address of j
D. Undefined behaviour
Answer: Option A
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A. Decision making
B. Code organization
C. Variable declaration
D. Storing values
In C, how do you declare a pointer variable that can store the address of an integer?
A. int *ptr;
B. ptr int;
C. int ptr;
D. ptr *int;
What is the purpose of the '->' operator in C when used with pointers?
A. Arithmetic operation
B. Indirection operator
C. Member access operator
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