What will be the output of the following C++ code?
#include <iostream>
#include <vector>
#include<iterator>
using namespace std;
int main ()
{
vector<int> myvector;
for (int i = 1; i <= 10; i++)
myvector.push_back(i);
myvector.erase (myvector.begin() + 6);
myvector.erase (myvector.begin(), myvector.begin() + 4);
for (unsigned i = 0; i < myvector.size(); ++i)
cout << ' ' << myvector[i];
return 0;
}
#include <iostream>
#include <vector>
#include<iterator>
using namespace std;
int main ()
{
vector<int> myvector;
for (int i = 1; i <= 10; i++)
myvector.push_back(i);
myvector.erase (myvector.begin() + 6);
myvector.erase (myvector.begin(), myvector.begin() + 4);
for (unsigned i = 0; i < myvector.size(); ++i)
cout << ' ' << myvector[i];
return 0;
}A. 5 6 7 8 9
B. 5 6 8 9 10
C. 6 7 8 9 10
D. 4 7 5 9 10
Answer: Option B
This Question Belongs to C Plus Plus Programming >> C Plus Plus Miscellaneous
What does the 'sizeof' operator return in C++?
A. Size of a data type in bits
B. Size of a data type in bytes
C. Size of a variable in bytes
D. Size of a variable in bits
What is the purpose of the 'static' keyword in C++?
A. To declare a variable with dynamic storage duration
B. To declare a constant
C. To declare a variable with external linkage
D. To declare a variable with static storage duration
What is the difference between '++i' and 'i++' in C++?
A. None of the above
B. They both have the same effect
C. '++i' increments the value of 'i' before returning it, while 'i++' increments the value of 'i' after returning it
D. '++i' increments the value of 'i' after returning it, while 'i++' increments the value of 'i' before returning it
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