What will be the output of the following code: for (int i = 5; i >= 0; --i) { cout << i << " "; if (i == 3) break; } in C++?
A. Compilation error
B. 5 4 3
C. 5 4 3 2 1 0
D. 5 4 3 0 1
Answer: Option B
Solution (By Examveda Team)
The given code is a for loop in C++:for (int i = 5; i >= 0; --i) {
cout << i << " ";
if (i == 3) break;
}
This loop initializes i to 5 and decrements it in each iteration until i becomes less than 0.
On each iteration, it prints the current value of i followed by a space.
When i becomes 3, the if condition becomes true and the break statement terminates the loop.
Therefore, the values printed are: 5 4 3
No further values (like 2, 1, 0) are printed because the loop exits when i == 3.
Hence, the correct output is: 5 4 3
This Question Belongs to C Plus Plus Programming >> Control Flow Statements In C Plus Plus
The given answer (Option C: 5 4 3 2 1 0) is incorrect.
The loop starts with i = 5 and decrements i each iteration:
i = 5 → prints 5
i = 4 → prints 4
i = 3 → prints 3
When i == 3, the break statement executes, which immediately terminates the loop. So the loop does not continue to 2, 1, or 0.
Therefore, the output is:
5 4 3
The correct answer is Option B (5 4 3).
the correct answer is
5 4 3
becuse the loop is stop when ( i = 3 )