What will be the output of the following program code?

#include<stdio.h>
void main()
{
      int i = 10;
      void *p = &i;
      printf("%f", *(float *)p);
}

Dayan Bhoi 5 years ago

Sabb ka galat hai bc

Abdulrhman Alyafai 6 years ago

int id = 0;

try{

if (id == 0)

throw new RuntimeException(“id is zero ”);

} catch(RuntimeException e){

System.out.print(e.getMessage());

}

finally{

System.out.println("Close Program");

}

Abhay Chhetri 6 years ago

since the value that we are de referencing is integer type thus type casting in floating type will give the output 0.000. but if we will type cast in integer type then the output will be 10.

Srav Shivkumar 8 years ago

when i execute this pgm i get an error stating main should return int.how is this showing 0.000? some pls explain

PRADEEPCHIN2 9 years ago

can anyone please explain this program.

Mayur Patil 9 years ago

i cannot understand this typecast
and output=0.000000

SAKSHI MISHRA 9 years ago

We can de-reference a void pointer by typecasting it to any of float, int or char pointers. Here we are accessing the de-referenced value (int i=10) but since we are printing %f we get 0.00000.

Ashish Munot 9 years ago

hey how it is possible

Ritanshi Jain 9 years ago

Can anyone plzz explain how is this answer correct

Komal Jha 9 years ago

How did the answer came 0.000

Akash Algikar 11 years ago

What is the solution anyone??