?
What will be the output of the program?
What will be the output of the program?
#include<stdio.h>
int main()
{
int arr[1] = {10};
printf("%d", 0[arr]);
return 0;
}
#include<stdio.h>
int main()
{
int arr[1] = {10};
printf("%d", 0[arr]);
return 0;
}
Answer & Solution
Correct Answer:
Option
C
>> int arr[1]={10}; The variable arr[1] is declared as an integer array with size '2' i.e. arr[0] and arr[1] and it's first element is initialized to value '10'(means arr[0]=10)
and arr[1] = garbage value or zero
>> printf("%d", 0[arr]); It prints the first element value of the variable arr.
Hence the output of the program is 10.
Join the Discussion
Login to post a comment or share your explanation.
Loginint main()
{
int arr[1] = {10}; // ={10,0);
printf("%d", 0[arr]); // *(arr+0)=arr[0]=10;
return 0;
}
output: 10
#include
int main()
{
int arr[1] = {10};
printf("%d", 1[arr]); // if *(arr+1)=arr[1]=0
return 0;
}
output: 0
even if size is 2 then elements are arr[0]=0
arr[1]=10
so first element should be 0