What will be the value stored in arr[5] when the following code is executed?
#include<stdio.h>
int cat_number(int n)
{
int i,j,arr[n],k;
arr[0] = 1;
for(i = 1; i < n; i++)
{
arr[i] = 0;
for(j = 0,k = i - 1; j < i; j++,k--)
arr[i] += arr[j] * arr[k];
}
return arr[n-1];
}
int main()
{
int ans, n = 10;
ans = cat_number(n);
printf("%d\n",ans);
return 0;
}
#include<stdio.h>
int cat_number(int n)
{
int i,j,arr[n],k;
arr[0] = 1;
for(i = 1; i < n; i++)
{
arr[i] = 0;
for(j = 0,k = i - 1; j < i; j++,k--)
arr[i] += arr[j] * arr[k];
}
return arr[n-1];
}
int main()
{
int ans, n = 10;
ans = cat_number(n);
printf("%d\n",ans);
return 0;
}A. 14
B. 42
C. 132
D. 429
Answer: Option B

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