Which smallest number must be added to 710 so that the sum is a perfect cube ?
A. 11
B. 19
C. 21
D. 29
Answer: Option B
Solution(By Examveda Team)
$$\eqalign{ & {\text{Required number to be added}} \cr & = {9^3} - 710 \cr & = 729 - 710 \cr & = 19 \cr} $$Related Questions on Square Root and Cube Root
The least perfect square, which is divisible by each of 21, 36 and 66 is:
A. 213444
B. 214344
C. 214434
D. 231444
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