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While working 7 hour a day, A alone can complete a piece of work in 6 days and B alone in 8 days. In what time would they complete it together, 8 hour a day?

A. 3 days

B. 4 days

C. 2.1 days

D. 3.6 days

Answer: Option A

Solution(By Examveda Team)

A can complete the work in 7 × 6 = 42 hours
1 hour's work of A = $$\frac{1}{{42}}$$
B can complete the work in 7 × 8 = 56 hours
1 hour's work of B = $$\frac{1}{{56}}$$
(A + B)'s 1 hour's work
$$\eqalign{ & = \frac{1}{{42}} + \frac{1}{{56}} \cr & = \frac{{4 + 3}}{{168}} \cr & = \frac{7}{{168}} \cr} $$
∴ Time taken by (A + B) working 8 hours daily
$$\frac{{168}}{{7 \times 8}} = 3\,{\text{days}}$$

This Question Belongs to Arithmetic Ability >> Time And Work

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Comments ( 3 )

  1. MD.Motiar Rahman
    MD.Motiar Rahman :
    3 years ago

    Thanks

  2. Md Ibrahim
    Md Ibrahim :
    6 years ago

    1/42+1/56=7/168*8=7/21
    3 days.

  3. Rahul
    Rahul :
    9 years ago

    A+B 1 hour work is 1/42+1/56
    see the solution

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