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LoginHence we need minimum 150 IP Address on each network. It means we cannot borrow a single bit from the last octet. Because, if you borrow a single bit you will get less then 150 IP Address.
So, we have to borrow 4 bits from the third octed. (24=16 Subnets) and here you will get (212 – 2 = 4094 IP Address) on each network.
(11111111.11111111.11110000.00000000)
(27 + 26 + 25 + 24 + 23 + 22 + 21 + 20) . (27 + 26 + 25 + 24 + 23 + 22 + 21 + 20) . (27 + 26 + 25 + 24) . (0)
So the subnet mask is 255.255.240.0 with maximum number of host.