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This question belongs to Arithmetic Ability Percentage
Percentage
?

X has twice as much money as that of Y and Y has 50% more money than that of Z. If the average money of all of them is Rs. 110, then the money, which X has is :

Answer & Solution
Correct Answer: Option D
50% = $$\frac{1}{2}$$
Let Z has 2 units of money
According to the question,
X   :   Y   :   Z
6   :   3   :   2
$$\frac{(6 + 3 + 2)}{3}$$   units = Rs. 110
⇒ 11 units = Rs. 330
    1 unit = Rs. 30
6 units = 30 × 6 = Rs. 180
Hence, X has Rs. 180
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