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x, y and z are distinct prime numbers where x < y < z. If x + y + z = 70, then what is the value of z?
Answer & Solution
Correct Answer:
Option
C
Since x, y and z are distinct prime number (x < y < z)
y + z = 70 - 2 = 68
31 + 37 = 68
Hence, x = 2, y = 31 and $$\boxed{{\text{z}} = 37}{\text{ Answer}}$$
y + z = 70 - 2 = 68
31 + 37 = 68
Hence, x = 2, y = 31 and $$\boxed{{\text{z}} = 37}{\text{ Answer}}$$
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