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16 children are to be divided into two groups A and B of 10 and 6 children. The average percent marks obtained by the children of group A is 75 and the average percent marks of all the 16 children is 76. What is the average percent marks of children of group B ?
Answer & Solution
Correct Answer:
Option
B
Required average
$$\eqalign{ & = \frac{{\left( {76 \times 16} \right) - \left( {75 \times 10} \right)}}{6} \cr & = \left( {\frac{{1216 - 750}}{6}} \right) \cr & = \frac{{466}}{6} \cr & = \frac{{233}}{3} \cr & = 77\frac{2}{3} \cr} $$
$$\eqalign{ & = \frac{{\left( {76 \times 16} \right) - \left( {75 \times 10} \right)}}{6} \cr & = \left( {\frac{{1216 - 750}}{6}} \right) \cr & = \frac{{466}}{6} \cr & = \frac{{233}}{3} \cr & = 77\frac{2}{3} \cr} $$
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